The product of the reaction between ethylbenz | vedclass

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Question

(B) $N$-bromosuccinimide $(NBS)$ is a reagent used for allylic or benzylic bromination via a free radical mechanism.In ethylbenzene $(C_6H_5CH_2CH_3)$

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$1-$bromo$-1-$phenylethane

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(B) $N$-bromosuccinimide $(NBS)$ is a reagent used for allylic or benzylic bromination via a free radical mechanism.In ethylbenzene $(C_6H_5CH_2CH_3)$,the benzylic position is the carbon atom directly attached to the benzene ring.The hydrogen atoms at the benzylic position are more reactive due to the stability of the resulting benzylic radical.Therefore,$NBS$ selectively replaces a hydrogen atom at the benzylic position with a bromine atom,yielding $1$-bromo-$1$-phenylethane $(C_6H_5CH(Br)CH_3)$.

The product of the reaction between ethylbenzene and $N$-bromosuccinimide $(NBS)$ is:

Similar Questions

Match the following reactions with their mechanisms:
$(A)$ $CH_3CH_2CH_2I \xrightarrow{aq. KOH}$
$(B)$ $(CH_3)_3CCl \xrightarrow{H_2O}$
$(I)$ $S_N1$
$(II)$ $E_2$
$(III)$ $S_N2$
$(IV)$ $E_1$

The given compound $CH_3-O-CH_2-Br$ undergoes which of the following reactions?

Identify the most suitable reagents $(I)$ and $(II)$ for the following sequence of reactions:

Which product is obtained from the reaction between $CH_3ONa$ and $(CH_3)_3CBr$?

In the given reaction $3-$Bromo$-2,2-$dimethylbutane $\xrightarrow{C_2H_5OH}$ (Major product) $'A'$. Product $A$ is:

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