The image formed by a concave mirror is

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(C) Using the mirror equation,$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Rearranging for image distance,$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$.For a

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certainly real if the object is virtual.

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(C) Using the mirror equation,$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Rearranging for image distance,$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$.For a concave mirror,the focal length $f$ is negative $(f If the object is virtual,the object distance $u$ is positive $(u > 0)$. Substituting these into the equation,$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$ results in a negative value for $\frac{1}{v}$,meaning $v If the object is real,the object distance $u$ is negative $(u < 0)$. In this case,the image distance $v$ can be positive or negative depending on whether the object is placed between the pole and the focus or beyond the focus.

Similar Questions

All of the following statements are correct except:

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