The hybridization of C_2 and C_3 in CH_3-CH=C | vedclass

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Question

(B) The structure of the given molecule is $CH_3-CH=C=CH-CH_3$.To determine the hybridization,we count the number of sigma bonds and lone pairs around

Vedclass · Accepted Answer

$sp^2, sp$

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(B) The structure of the given molecule is $CH_3-CH=C=CH-CH_3$.To determine the hybridization,we count the number of sigma bonds and lone pairs around the carbon atom.For $C_2$: It is bonded to one $H$ atom,one $CH_3$ group (single bond),and one $C_3$ atom (double bond). It has $3$ sigma bonds and $0$ lone pairs,so it is $sp^2$ hybridized.For $C_3$: It is bonded to $C_2$ (double bond) and $C_4$ (double bond). It has $2$ sigma bonds and $0$ lone pairs,so it is $sp$ hybridized.Therefore,the hybridization of $C_2$ and $C_3$ is $sp^2$ and $sp$ respectively.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

The hybridization of $C_2$ and $C_3$ in $CH_3-CH=C=CH-CH_3$ is

Similar Questions

In the compound $CH_2=CH-CH_2-C \equiv CH$,what is the hybridization type of the $C_2-C_3$ bond?

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

What is the hybridization state of carbon atoms $1, 2, 3,$ and $4$ in the given reaction?

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2 \ sp$ carbons
$B$. Ethylene $2$. $6 \ sp^2$ carbons
$C$. Acetylene $3$. $2 \ sp^3$ carbons
$D$. Benzene $4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

The compounds containing $sp$-hybridised carbon atom are:
$(I)$ $H_3C-N(CH_3)-CHO$
$(II)$ Pyridine
$(III)$ $H_3C-CN$
$(IV)$ $H_2C=C=CH-CH_3$

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