The horizontal component of the earth's magne | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The induced $e.m.f.$ in a rod moving in a magnetic field is given by $\varepsilon = B_{\perp} \ell v$,where $B_{\perp}$ is the vertical component

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) The induced $e.m.f.$ in a rod moving in a magnetic field is given by $\varepsilon = B_{\perp} \ell v$,where $B_{\perp}$ is the vertical component of the earth's magnetic field $(B_v)$.The vertical component is related to the horizontal component $(B_H)$ and the angle of dip $(\delta)$ by $B_v = B_H 	an \delta$.Given: $B_H = 3 	imes 10^{-4} \ T$,$\delta = 	an^{-1}(4/3)$,$\ell = 0.25 \ m$,and $v = 10 \ cm/s = 0.1 \ m/s$.Substituting the values:$B_v = (3 	imes 10^{-4}) 	imes (4/3) = 4 	imes 10^{-4} \ T$.Now,calculate the $e.m.f.$:$\varepsilon = B_v \ell v = (4 	imes 10^{-4}) 	imes 0.25 	imes 0.1$.$\varepsilon = 1 	imes 10^{-4} 	imes 0.1 = 10^{-5} \ V$.Converting to $\mu V$:$\varepsilon = 10 	imes 10^{-6} \ V = 10 \ \mu V$.

Similar Questions

$A$ rod of length $2 \, m$ slides with a speed of $5 \, ms^{-1}$ on a rectangular conducting frame as shown in the figure. There exists a uniform magnetic field of $0.04 \, T$ perpendicular to the plane of the figure. If the resistance of the rod is $3 \, \Omega$, the current through the rod is

Two infinitely long conducting parallel rails are connected through a capacitor $C$ as shown in the figure. $A$ conductor of length $l$ is moved with constant speed $v_0$. Which of the following graphs truly depicts the variation of current through the conductor with time?

As shown in the figure,a metal rod makes contact and completes the circuit. The circuit is perpendicular to the magnetic field with $B = 0.15 \, T$. If the resistance is $3 \, \Omega$,the force needed to move the rod as indicated with a constant speed of $2 \, m/s$ is:

$A$ conducting rod of length $L$ rotates with angular speed $\omega$ in a uniform magnetic field of induction $B$ which is perpendicular to its motion. The induced emf developed between the two ends of the rod is

$A$ square loop of side $a$ and resistance $R$ is moved in a region of uniform magnetic field $B$ (the loop remaining completely inside the field) with a velocity $v$ through a distance $x$. The work done is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module