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(B) The partial pressure of $N_2$ is given by $P_{N_2} = \chi_{N_2} 	imes P_{total} = 0.8 	imes 5 \, atm = 4 \, atm$.According to Henry's law,$P_{N_

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$4 	imes 10^{-4}$

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(B) The partial pressure of $N_2$ is given by $P_{N_2} = \chi_{N_2} 	imes P_{total} = 0.8 	imes 5 \, atm = 4 \, atm$.According to Henry's law,$P_{N_2} = K_H 	imes x_{N_2}$,where $x_{N_2}$ is the mole fraction of $N_2$ in the solution.$4 = 1 	imes 10^5 	imes x_{N_2} \Rightarrow x_{N_2} = 4 	imes 10^{-5}$.Since $x_{N_2} = \frac{n_{N_2}}{n_{N_2} + n_{H_2O}} \approx \frac{n_{N_2}}{n_{H_2O}}$ (as $n_{N_2}$ is very small compared to $n_{H_2O}$),$4 	imes 10^{-5} = \frac{n_{N_2}}{10} \Rightarrow n_{N_2} = 4 	imes 10^{-4} \, moles$.

Gas	$K_{H} \ (kbar)$
$\alpha$	$50$
$\beta$	$2$
$\gamma$	$2 \times 10^{-5}$
$\delta$	$0.5$

The Henry's law constant for the solubility of $N_2$ gas in water at $25 \, ^oC$ is $1 \times 10^5 \, atm$. The mole fraction of $N_2$ in air is $0.8$. Calculate the number of moles of $N_2$ from air that will dissolve in $10 \, moles$ of $H_2O$ at $25 \, ^oC$ and at a total pressure of $5 \, atm$.

Similar Questions

At $298 \ K$,how many millimoles of $CO_2$ gas will dissolve in $900 \ mL$ of water when $CO_2$ gas is passed through it? The $K_H$ value is $6.02 \times 10^{-4} \ bar$ and the partial pressure of $CO_2$ gas is $2 \times 10^{-8} \ bar$.

Henry's constant (in $kbar$) for four gases $\alpha, \beta, \gamma$ and $\delta$ in water at $298 \ K$ is given below:

Gas $K_{H} \ (kbar)$

$\alpha$ $50$

$\beta$ $2$

$\gamma$ $2 \times 10^{-5}$

$\delta$ $0.5$

(Density of water $= 10^{3} \ kg \ m^{-3}$ at $298 \ K$). This table implies that:

What is the solubility of oxygen gas in $100 \, cm^3$ of water at $293 \, K$ (in $, cm^3$)?

The Henry's law constant for the solubility of $N_2$ gas in water at $298 \ K$ is $1.0 \times 10^5 \ atm$. The mole fraction of $N_2$ in air is $0.8$. Calculate the number of moles of $N_2$ dissolved in $10 \ moles$ of water at $298 \ K$ and a total pressure of $5 \ atm$.

Explain the solubility rule "like dissolves like" in terms of inter-molecular forces that exist in solutions.

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