The height at which the weight of the body becomes $\frac{1}{16}$ of its weight on the surface of the earth of radius $R$ is: (in $R$)

$A$ body weighs $72 \ N$ on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth (in $N$)?

$A$ point mass of $10 \,kg$ is placed at the centre of the Earth. The weight of the point mass is

If the value of $g$ (acceleration due to gravity) at the Earth's surface is $10 \ m/s^2$,what is its value in $m/s^2$ at the center of the Earth,assuming the Earth is a sphere of radius $R$ meters with uniform mass density?

Assuming the Earth to be a sphere of uniform density, the acceleration due to gravity:

If both the mass and the radius of the earth decrease by $1\%$,the value of the acceleration due to gravity will