(A) The atomic masses of the given elements are: $1$. Uranium $(U)$: $238.03 \ u$ $2$. Radium $(Ra)$: $226.03 \ u$ $3$. Lead $(Pb)$: $207.2 \ u$ $4$.

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(A) The atomic masses of the given elements are: $1$. Uranium $(U)$: $238.03 \ u$ $2$. Radium $(Ra)$: $226.03 \ u$ $3$. Lead $(Pb)$: $207.2 \ u$ $4$. Mercury $(Hg)$: $200.59 \ u$ Comparing these values,Uranium has the highest atomic mass. Therefore,the correct option is $A$.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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The heaviest atom amongst the following is

A
Uranium
B
Radium
C
Lead
D
Mercury

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Class 11 Questions

Class 11

Chemistry Questions

Chapter

Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

The vapour density of the methyl ester of an organic monocarboxylic acid is $37$. What is the molecular weight of the acid?

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The equivalent mass of a metal is $29.73$ and the vapour density of its chloride is $130.4$. Find out the atomic mass of the metal.

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$A$ metal $M$ (specific heat $0.16 \ J \ g^{-1} \ K^{-1}$) forms a metal chloride with $65\%$ chlorine present in it. The formula of the metal chloride will be:

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In Victor Mayer’s method,$0.2 \ g$ of an organic substance displaced $56 \ mL$ of air at $STP$. The molecular weight of the compound is:

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The modern basis of atomic weight is

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The heaviest atom amongst the following is

Similar Questions

The vapour density of the methyl ester of an organic monocarboxylic acid is $37$. What is the molecular weight of the acid?

The equivalent mass of a metal is $29.73$ and the vapour density of its chloride is $130.4$. Find out the atomic mass of the metal.

$A$ metal $M$ (specific heat $0.16 \ J \ g^{-1} \ K^{-1}$) forms a metal chloride with $65\%$ chlorine present in it. The formula of the metal chloride will be:

In Victor Mayer’s method,$0.2 \ g$ of an organic substance displaced $56 \ mL$ of air at $STP$. The molecular weight of the compound is:

The modern basis of atomic weight is

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