The half-life of radioisotopic bromine $-82$ is $36 \ hours$. The fraction which remains after one day is . . . . . . $\times 10^{-2}$. (Given $\text{antilog } 0.2006 = 1.587$)

  • A
    $41$
  • B
    $52$
  • C
    $63$
  • D
    $36$

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