(B) For $A$,$t_{1/2} = 1 \ min$. After $4 \ min$ ($4$ half-lives),the fraction of $A$ remaining is $(1/2)^4 = 1/16$. Therefore,the fraction of $A$ dis

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(B) For $A$,$t_{1/2} = 1 \ min$. After $4 \ min$ ($4$ half-lives),the fraction of $A$ remaining is $(1/2)^4 = 1/16$. Therefore,the fraction of $A$ disintegrated is $1 - 1/16 = 15/16$. For $B$,$t_{1/2} = 2 \ min$. After $4 \ min$ ($2$ half-lives),the fraction of $B$ remaining is $(1/2)^2 = 1/4$. Therefore,the fraction of $B$ disintegrated is $1 - 1/4 = 3/4$. The ratio of disintegrated weights of $A$ and $B$ is $(15/16) : (3/4) = 15/16 : 12/16 = 15:12 = 5:4$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

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The half-lives of two radioactive nuclides $A$ and $B$ are $1 \ min$ and $2 \ min$ respectively. Equal weights of $A$ and $B$ are taken separately and allowed to disintegrate for $4 \ min$. What will be the ratio of weights of $A$ and $B$ disintegrated?

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A
$1:1$
B
$5:4$
C
$1:2$
D
$1:3$

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Nuclear Chemistry

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Rate of decay and Half-life

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$8 \ g$ of a radioactive substance is reduced to $0.5 \ g$ after $1 \ hour$. The ${t_{1/2}}$ of the radioactive substance is ......... $\min$.

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The half-life of a radioactive substance is $120$ days. After $480$ days,the amount of $4 \ g$ of the substance remaining will be: (in $g$)

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After $2 \, \text{hours}$,the amount of a certain radioactive substance reduces to $1/16^{th}$ of the original amount (the decay process follows first-order kinetics). The half-life of the radioactive substance is $...... \, \text{min}$.

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The rate of radioactive disintegration at an instant for a radioactive sample of half-life $2.2 \times 10^{9} \ s$ is $10^{10} \ s^{-1}$. The number of radioactive atoms in that sample at that instant is:

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The half-lives of two radioactive nuclides $A$ and $B$ are $1 \ min$ and $2 \ min$ respectively. Equal weights of $A$ and $B$ are taken separately and allowed to disintegrate for $4 \ min$. What will be the ratio of weights of $A$ and $B$ disintegrated?

Similar Questions

$8 \ g$ of a radioactive substance is reduced to $0.5 \ g$ after $1 \ hour$. The ${t_{1/2}}$ of the radioactive substance is ......... $\min$.

The half-life of a radioisotope is $20 \ hours$. After $60 \ hours$,what fraction of the initial amount will remain?

The half-life of a radioactive substance is $120$ days. After $480$ days,the amount of $4 \ g$ of the substance remaining will be: (in $g$)

After $2 \, \text{hours}$,the amount of a certain radioactive substance reduces to $1/16^{th}$ of the original amount (the decay process follows first-order kinetics). The half-life of the radioactive substance is $...... \, \text{min}$.

The rate of radioactive disintegration at an instant for a radioactive sample of half-life $2.2 \times 10^{9} \ s$ is $10^{10} \ s^{-1}$. The number of radioactive atoms in that sample at that instant is:

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