The graphs below show angular velocity omega | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The angular acceleration $\alpha$ is defined as the rate of change of angular velocity with respect to time,given by $\alpha = \frac{d\omega}{dt}$

Vedclass · Accepted Answer

Vedclass · Answer

(A) The angular acceleration $\alpha$ is defined as the rate of change of angular velocity with respect to time,given by $\alpha = \frac{d\omega}{dt}$.Graphically,$\alpha$ represents the slope of the $\omega-t$ graph.The magnitude of the angular acceleration is $|\alpha| = |\frac{d\omega}{dt}|$,which corresponds to the steepness (absolute value of the slope) of the tangent to the curve at any point.In graph $A$,the curve starts with a steep slope and becomes flatter as $t$ increases. This means the slope $\frac{d\omega}{dt}$ is positive and its magnitude is decreasing over time.In graph $B$,the slope is constant,so $\alpha$ is constant.In graph $C$,the slope is constant (negative),so the magnitude of $\alpha$ is constant.In graph $D$,the curve becomes steeper as $t$ increases,meaning the magnitude of the slope is increasing.Therefore,the magnitude of the angular acceleration is constantly decreasing in graph $A$.

The graphs below show angular velocity $\omega$ as a function of time $t$. In which one is the magnitude of the angular acceleration $\alpha$ constantly decreasing?

Similar Questions

$A$ metal sphere of radius $r$ and specific heat $S$ is rotated about an axis passing through its centre at a speed of $n$ rotations per second. It is suddenly stopped and $50 \%$ of its energy is used in increasing its temperature. Then,the rise in temperature of the sphere is

Seven identical circular planar disks,each of mass $M$ and radius $R$,are welded symmetrically as shown. The moment of inertia of the arrangement about the axis normal to the plane and passing through the point $P$ is:

The angular momentum of a particle performing uniform circular motion is $L$. If the kinetic energy of the particle is doubled and the frequency is halved,then the new angular momentum becomes:

$A$ ring of mass $M$ and radius $R$ sliding with a velocity $v_0$ suddenly enters a rough surface where the coefficient of friction is $\mu$,as shown in the figure. Choose the correct alternative$(s)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module