The graph of the pair of equations 3x + 4y = | vedclass

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(C) Given equations are:$3x + 4y = 10$  --- $(1)$$3x + 4y = 15$  --- $(2)$Comparing these with the standard form $a_1x + b_1y = c_1$ and $a_2x + b_2y

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parallel lines

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(C) Given equations are:$3x + 4y = 10$  --- $(1)$$3x + 4y = 15$  --- $(2)$Comparing these with the standard form $a_1x + b_1y = c_1$ and $a_2x + b_2y = c_2$:$a_1 = 3, b_1 = 4, c_1 = 10$$a_2 = 3, b_2 = 4, c_2 = 15$Now,find the ratios:$\frac{a_1}{a_2} = \frac{3}{3} = 1$$\frac{b_1}{b_2} = \frac{4}{4} = 1$$\frac{c_1}{c_2} = \frac{10}{15} = \frac{2}{3}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel to each other and do not intersect.

The graph of the pair of equations $3x + 4y = 10$ and $3x + 4y = 15$ represents:

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