The graph of the equation ldots ldots ldots l | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) line is parallel to the $Y$-axis if its equation is of the form $x = k$,where $k$ is a constant.Checking the options:$A$) $3y - 1 = 0 \implies y =

Vedclass · Accepted Answer

$2x + 5 = 0$

Vedclass · Answer

(B) line is parallel to the $Y$-axis if its equation is of the form $x = k$,where $k$ is a constant.Checking the options:$A$) $3y - 1 = 0 \implies y = 1/3$ (This is a line parallel to the $X$-axis).$B$) $2x + 5 = 0 \implies 2x = -5 \implies x = -2.5$ (This is a line parallel to the $Y$-axis).$C$) $2x + 3y = 1$ (This is a slanted line intersecting both axes).$D$) $2x - 3y = 1$ (This is a slanted line intersecting both axes).Therefore,the correct option is $B$.

The graph of the equation $\ldots \ldots \ldots \ldots$ is parallel to the $Y$-axis.

Similar Questions

Solve the following pair of linear equations:
$x + y = 3.3$
$\frac{0.6}{3x - 2y} = -1$,where $3x - 2y \neq 0$

$(-1, 3)$ is not a solution of the equation $\ldots \ldots \ldots \ldots$

For a pair of equations $5x - 4y = 1$ and $10x = 8y + 2$,in usual notations $a_{1}b_{2} - a_{2}b_{1} = \dots$

Find the solution of the pair of equations $\frac{x}{10} + \frac{y}{5} - 1 = 0$ and $\frac{x}{8} + \frac{y}{6} = 15$. Hence,find $\lambda$ if $y = \lambda x + 5$.

$A$ pair of linear equations which has a unique solution $x=2, y=-3$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module