Solve the following pair of linear equations: | vedclass

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(C) Given equations are:$(i) \ x + y = 3.3$$(ii) \ \frac{0.6}{3x - 2y} = -1$From equation $(ii)$:$0.6 = -1(3x - 2y)$$0.6 = -3x + 2y$$3x - 2y = -0.6 \q

Vedclass · Accepted Answer

$1.2, 2.1$

Vedclass · Answer

(C) Given equations are:$(i) \ x + y = 3.3$$(ii) \ \frac{0.6}{3x - 2y} = -1$From equation $(ii)$:$0.6 = -1(3x - 2y)$$0.6 = -3x + 2y$$3x - 2y = -0.6 \quad (iii)$To solve the system,multiply equation $(i)$ by $2$:$2x + 2y = 6.6 \quad (iv)$Add equation $(iii)$ and $(iv)$:$(3x - 2y) + (2x + 2y) = -0.6 + 6.6$$5x = 6$$x = \frac{6}{5} = 1.2$Substitute $x = 1.2$ into equation $(i)$:$1.2 + y = 3.3$$y = 3.3 - 1.2$$y = 2.1$Thus,the solution is $x = 1.2$ and $y = 2.1$.

Solve the following pair of linear equations:
$x + y = 3.3$
$\frac{0.6}{3x - 2y} = -1$,where $3x - 2y \neq 0$

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Solve the following pair of linear equations:$x + y = 3.3$$\frac{0.6}{3x - 2y} = -1$,where $3x - 2y \neq 0$