The graph given below is the distance$-$time graph of an object.

$(i)$ Find the speed of the object during first four seconds of its journey.

$(ii)$ How long was it stationary ?

$(iii)$ Does it represent a real situation ? Justify your answer.

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$(i)$ $OP$ indicates uniform speed given

$v=\frac{75-0}{4-0}=\frac{75}{4}=18.75 m s ^{-1}$

$(ii)$ $PQ$ is parallel to the time axis. It indicates that the object is stationary. It is a real situation.

$(iii)$ $QR$ shows that distance and time decreases, which is not possible. Thus, this is not a real situation.

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