The given figure shows a network of resistanc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) battery is getting charged when the current enters through its positive terminal. Let the potential at point $D$ be $0\,V$. Since the $12\,V$ batt

Vedclass · Accepted Answer

$8\,V$ battery

Vedclass · Answer

(A) battery is getting charged when the current enters through its positive terminal. Let the potential at point $D$ be $0\,V$. Since the $12\,V$ battery is connected between $A$ and $C$,let $V_A = 12\,V$ and $V_C = 0\,V$. The circuit is a Wheatstone bridge. The resistances are $R_{AB} = 4\,\Omega$,$R_{BC} = 4\,\Omega$,$R_{AD} = 4\,\Omega$,and $R_{DC} = 4\,\Omega$. Since $R_{AB}/R_{AD} = R_{BC}/R_{DC} = 4/4 = 1$,the bridge is balanced. The potential at $B$ is the same as the potential at $D$ if there were no battery. With the $8\,V$ battery connected between $B$ and $D$ (positive terminal at $B$),the potential $V_B = 8\,V$ and $V_D = 0\,V$. For the $12\,V$ battery,current flows from $A$ to $C$ through the external circuit,meaning it is discharging. For the $8\,V$ battery,the potential at $B$ is $8\,V$ and the potential at $D$ is $0\,V$. The current from the $12\,V$ battery flows through the branches $AB$ and $AD$. Calculating the potentials: $V_B = V_A - I_{AB}R_{AB} = 12 - I_{AB}(4)$. In a balanced bridge,the current flows from $A$ to $B$ and $A$ to $D$. The potential at $B$ due to the $12\,V$ source is $V_B = 12 	imes (4/(4+4)) = 6\,V$. Since the actual potential at $B$ is $8\,V$ (due to the battery),current flows from $B$ to $A$ and $B$ to $C$. Thus,current enters the $8\,V$ battery through its positive terminal,so the $8\,V$ battery is getting charged.

The given figure shows a network of resistances and two batteries. Which of the two batteries is getting charged?

Similar Questions

For the circuit shown below,write the equations for the three loops by using Kirchhoff's loop rule.

Five resistances are connected as shown in the figure. The effective resistance between the points $A$ and $B$ is

$A$ battery of $10 \;V$ and negligible internal resistance is connected across the diagonally opposite corners of a cubical network consisting of $12$ resistors each of resistance $1 \;\Omega$. Determine the equivalent resistance of the network and the current along each edge of the cube.

The value of current $I$ in the given circuit is (in $A$)

If the resistances are chosen for the circuit shown in the figure in such a way that no current flows through the battery with emf $E_1 = 2 \ V$,the voltage $V_2$ across $R_2$ and the current $I_3$ flowing through $R_3$ are respectively,

Vedclass Test Series

Exam Paper Generator

Online Exam Module