The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.
Runs scored Number of batsmen $3000-4000$ $4$ $4000-5000$ $18$ $5000-6000$ $9$ $6000-7000$ $7$ $7000-8000$ $6$ $8000-9000$ $3$ $9000-10000$ $1$ $10000-11000$ $1$
Find the mode of the data.
| Runs scored | Number of batsmen |
| $3000-4000$ | $4$ |
| $4000-5000$ | $18$ |
| $5000-6000$ | $9$ |
| $6000-7000$ | $7$ |
| $7000-8000$ | $6$ |
| $8000-9000$ | $3$ |
| $9000-10000$ | $1$ |
| $10000-11000$ | $1$ |
Find the mode of the data.
- A$3608.7$
- B$4985.50$
- C$4500$
- D$4608.7$
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Similar Questions
The lengths of $40$ leaves of a plant are measured correct to the nearest millimetre,and the data obtained is represented in the following table:
Length (in mm) Number of leaves $118-126$ $3$ $127-135$ $5$ $136-144$ $9$ $145-153$ $12$ $154-162$ $5$ $163-171$ $4$ $172-180$ $2$
Find the median length of the leaves.
| Length (in mm) | Number of leaves |
| $118-126$ | $3$ |
| $127-135$ | $5$ |
| $136-144$ | $9$ |
| $145-153$ | $12$ |
| $154-162$ | $5$ |
| $163-171$ | $4$ |
| $172-180$ | $2$ |
Find the median length of the leaves.
Medium
View Solution$A$ life insurance agent found the following data for the distribution of ages of $100$ policy holders. Calculate the median age,if policies are given only to persons having age $18$ years onwards but less than $60$ years.
Age (in years) Number of policy holders Below $20$ $2$ Below $25$ $6$ Below $30$ $24$ Below $35$ $45$ Below $40$ $78$ Below $45$ $89$ Below $50$ $92$ Below $55$ $98$ Below $60$ $100$
| Age (in years) | Number of policy holders |
| Below $20$ | $2$ |
| Below $25$ | $6$ |
| Below $30$ | $24$ |
| Below $35$ | $45$ |
| Below $40$ | $78$ |
| Below $45$ | $89$ |
| Below $50$ | $92$ |
| Below $55$ | $98$ |
| Below $60$ | $100$ |
Difficult
View SolutionIf the median of the distribution given below is $28.5,$ find the values of $x$ and $y$.
Class interval Frequency $0-10$ $5$ $10-20$ $x$ $20-30$ $20$ $30-40$ $15$ $40-50$ $y$ $50-60$ $5$ Total $60$
| Class interval | Frequency |
| $0-10$ | $5$ |
| $10-20$ | $x$ |
| $20-30$ | $20$ |
| $30-40$ | $15$ |
| $40-50$ | $y$ |
| $50-60$ | $5$ |
| Total | $60$ |
Difficult
View Solution$A$ survey regarding the heights (in $cm$) of $51$ girls of Class $X$ of a school was conducted and the following data was obtained:
Height (in $cm$) Number of girls Less than $140$ $4$ Less than $145$ $11$ Less than $150$ $29$ Less than $155$ $40$ Less than $160$ $46$ Less than $165$ $51$
Find the median height.
| Height (in $cm$) | Number of girls |
| Less than $140$ | $4$ |
| Less than $145$ | $11$ |
| Less than $150$ | $29$ |
| Less than $155$ | $40$ |
| Less than $160$ | $46$ |
| Less than $165$ | $51$ |
Find the median height.
Easy
View SolutionThe annual profits earned by $30$ shops of a shopping complex in a locality give rise to the following distribution:
Profit (Rs in lakhs) Number of shops (frequency) More than or equal to $5$ $30$ More than or equal to $10$ $28$ More than or equal to $15$ $16$ More than or equal to $20$ $14$ More than or equal to $25$ $10$ More than or equal to $30$ $7$ More than or equal to $35$ $3$
Draw both ogives for the data above. Hence,obtain the median profit.
| Profit (Rs in lakhs) | Number of shops (frequency) |
| More than or equal to $5$ | $30$ |
| More than or equal to $10$ | $28$ |
| More than or equal to $15$ | $16$ |
| More than or equal to $20$ | $14$ |
| More than or equal to $25$ | $10$ |
| More than or equal to $30$ | $7$ |
| More than or equal to $35$ | $3$ |
Draw both ogives for the data above. Hence,obtain the median profit.
Medium
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