The geometry of XeOF_4 is | vedclass

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(D) $I$. The central atom $Xe$ has $8$ valence electrons. $II$. It forms one double bond with $O$ and four single bonds with $F$ atoms,utilizing $6$ e

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square pyramidal

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(D) $I$. The central atom $Xe$ has $8$ valence electrons. $II$. It forms one double bond with $O$ and four single bonds with $F$ atoms,utilizing $6$ electrons for bonding. $III$. This leaves one lone pair of electrons on $Xe$. $IV$. According to $VSEPR$ theory,with $5$ bond pairs and $1$ lone pair,the steric number is $6$,which corresponds to an octahedral electron geometry. $V$. Due to the presence of one lone pair,the molecular geometry is square pyramidal.

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

The geometry of $XeOF_4$ is

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Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

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