The general solution of the differential equation $\frac{dy}{dx} = 1 - x + y - xy$ is (where $C$ is a constant of integration)

  • A
    $\log(1+y) = x + \frac{x^2}{2} + C$
  • B
    $\log(1-x) = \log(1+y) + y + C$
  • C
    $\log(1+y) = y - \frac{x^2}{2} + C$
  • D
    $\log(1+y) = x - \frac{x^2}{2} + C$

Explore More

Similar Questions

The general solution of the differential equation $\frac{dy}{dx} = e^{x+y} + x^2 e^{x^3+y}$ is (where $C$ is a constant of integration):

The solution of the equation $\frac{dy}{dx} = \frac{y^2 - y - 2}{x^2 + 2x - 3}$ is

The solution of the differential equation $(1 + x^2)\frac{dy}{dx} = x$ is

The solution of the differential equation $\cos x \cos y \frac{dy}{dx} = - \sin x \sin y$ is

The equation of a curve passing through the origin,if the slope of the tangent drawn at any of its points $(x, y)$ is $\cos (x + y) + \sin (x + y)$,is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo