The fusion of chromite ore with sodium carbon | vedclass

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(B) The chemical reaction for the fusion of chromite ore $(FeCr_2O_4)$ with sodium carbonate $(Na_2CO_3)$ in the presence of air is:$4FeCr_2O_4 + 8Na_

Vedclass · Accepted Answer

$6$

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(B) The chemical reaction for the fusion of chromite ore $(FeCr_2O_4)$ with sodium carbonate $(Na_2CO_3)$ in the presence of air is:$4FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2$Here,$A = Na_2CrO_4$ and $B = Fe_2O_3$.$1$. For $Na_2CrO_4$ $(Cr^{6+})$: The electronic configuration is $[Ar]3d^0$. The number of unpaired electrons $(n)$ is $0$. Therefore,the spin-only magnetic moment $\mu_s = \sqrt{0(0+2)} = 0 \ B.M.$$2$. For $Fe_2O_3$ $(Fe^{3+})$: The electronic configuration is $[Ar]3d^5$. The number of unpaired electrons $(n)$ is $5$. Therefore,the spin-only magnetic moment $\mu_s = \sqrt{5(5+2)} = \sqrt{35} \approx 5.91 \ B.M.$Sum of magnetic moments $= 0 + 5.91 = 5.91 \ B.M.$The nearest integer value is $6$.

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