(D) For a pipe closed at one end,the fundamental frequency is given by $n_1 = \frac{V}{4L} = 100 \ Hz$. When the same pipe is open at both ends,the ne

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(D) For a pipe closed at one end,the fundamental frequency is given by $n_1 = \frac{V}{4L} = 100 \ Hz$. When the same pipe is open at both ends,the new fundamental frequency $n'_1$ is given by $n'_1 = \frac{V}{2L}$. Comparing the two expressions,we get $n'_1 = 2 \times \frac{V}{4L} = 2 \times 100 \ Hz = 200 \ Hz$. In an open pipe,all harmonics (integer multiples of the fundamental frequency) are produced. Therefore,the frequencies produced are $200 \ Hz, 400 \ Hz, 600 \ Hz, 800 \ Hz, .....$.

Class 11 Physics Waves and Sound Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

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The fundamental frequency of an air column in a pipe closed at one end is $100 \ Hz$. If the same pipe is open at both the ends,the frequencies produced in $Hz$ are

MHT CET 2017 All MHT CET

A
$100, 200, 300, 400, .....$
B
$100, 300, 500, 700, .....$
C
$200, 300, 400, 500, .....$
D
$200, 400, 600, 800, .....$

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Class 11

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Waves and Sound

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Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

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$A$ pipe $30 \, cm$ long is open at both ends. Which harmonic mode of the pipe resonates with a $1.1 \, kHz$ source? (Speed of sound in air $= 330 \, m/s$)

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The fundamental frequency of a closed pipe is $400 \text{ Hz}$. If $\left(\frac{1}{3}\right)^{rd}$ length of the pipe is filled with water, the frequency of the $2^{\text{nd}}$ harmonic of the pipe will be (Neglect end correction). (in $\text{ Hz}$)

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The stationary wave $y = 2a \sin kx \cos \omega t$ in a closed organ pipe is the result of the superposition of $y = a \sin (\omega t - kx)$ and

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The fundamental frequency of an air column in a pipe closed at one end is $100 \ Hz$. If the same pipe is open at both the ends,the frequencies produced in $Hz$ are

Similar Questions

$A$ pipe $30 \, cm$ long is open at both ends. Which harmonic mode of the pipe resonates with a $1.1 \, kHz$ source? (Speed of sound in air $= 330 \, m/s$)

If $v$ is the speed of sound in air,then what is the shortest length of a closed pipe that resonates at a frequency $n$?

$A$ closed organ pipe has a fundamental frequency $n$. If its length is doubled and its radius is halved,its fundamental frequency nearly becomes-

The fundamental frequency of a closed pipe is $400 \text{ Hz}$. If $\left(\frac{1}{3}\right)^{rd}$ length of the pipe is filled with water, the frequency of the $2^{\text{nd}}$ harmonic of the pipe will be (Neglect end correction). (in $\text{ Hz}$)

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