The formula to find the median of a grouped data is $\ldots \ldots \ldots \ldots .$
- A$M = 3Z - 2\bar{x}$
- B$M = l + \left( \frac{\frac{n}{2} - cf}{f} \right) \times h$
- C$M = l + \left( \frac{\frac{n}{2} - cf}{f_1 - f_2} \right) \times h$
- D$M = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h$
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Similar Questions
In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times c$ for the median,$cf = \ldots \ldots \ldots$
Easy
View SolutionFor a given frequency distribution,$n=100, A=20$ and $\bar{x}=20$. Then,$\Sigma f_{i} d_{i}=\ldots \ldots \ldots . .$
Medium
View SolutionFor the calculation of mode of the following frequency distribution,$f_{0} = \dots \dots \dots \dots \dots$
Class $1-3$ $3-5$ $5-7$ $7-9$ $9-11$ Frequency $6$ $3$ $8$ $2$ $1$
| Class | $1-3$ | $3-5$ | $5-7$ | $7-9$ | $9-11$ |
| Frequency | $6$ | $3$ | $8$ | $2$ | $1$ |
Easy
View SolutionIf $Z = 36.8$ and $M = 33.6$,then $\bar{x} = \ldots \ldots \ldots \ldots .$
Medium
View SolutionFind the mean of the following frequency distribution:
Class
$21-25$
$26-30$
$31-35$
$36-40$
$41-45$
$46-50$
$51-55$
Frequency
$18$
$32$
$30$
$40$
$25$
$15$
$40$
(in $.675$)
| Class | $21-25$ | $26-30$ | $31-35$ | $36-40$ | $41-45$ | $46-50$ | $51-55$ |
| Frequency | $18$ | $32$ | $30$ | $40$ | $25$ | $15$ | $40$ |
Easy
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