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(C) The force per unit length between two long parallel wires carrying currents $I_1$ and $I_2$ separated by a distance $y$ is given by the formula:$F

Vedclass · Accepted Answer

$\frac{F}{4}$

Vedclass · Answer

(C) The force per unit length between two long parallel wires carrying currents $I_1$ and $I_2$ separated by a distance $y$ is given by the formula:$F = \frac{\mu_0 I_1 I_2}{2 \pi y}$Given that both wires carry the same current $I$,the initial force is:$F = \frac{\mu_0 I^2}{2 \pi y}$If the current in each wire is halved,the new current becomes $I' = \frac{I}{2}$.The new force $F'$ is:$F' = \frac{\mu_0 (I/2) (I/2)}{2 \pi y} = \frac{\mu_0 I^2}{4 \cdot 2 \pi y}$Substituting the original force $F$ into this equation:$F' = \frac{1}{4} F$Therefore,the force becomes $\frac{F}{4}$.

The force between two long parallel wires is $F$ when each one of them carries a certain current $I$. If the current in each is halved,the force between them would be . . . . . . .

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