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(D) The magnetic field $B$ produced by an infinitely long straight wire carrying current $i_1$ at a distance $r$ is given by $B = \frac{\mu_0 i_1}{2\p

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(D) The magnetic field $B$ produced by an infinitely long straight wire carrying current $i_1$ at a distance $r$ is given by $B = \frac{\mu_0 i_1}{2\pi r}$.This magnetic field is directed perpendicular to the plane of the loop (into or out of the page).The force on each segment of the rectangular loop is given by $F = \int i_2 (dl 	imes B)$.For the two vertical segments of length $l$,the forces are $F_1 = \frac{\mu_0 i_1 i_2 l}{2\pi a}$ (attractive) and $F_2 = \frac{\mu_0 i_1 i_2 l}{2\pi b}$ (repulsive).For the two horizontal segments,the forces are equal and opposite,thus canceling each other out.Since all these forces act in the plane of the loop and their lines of action pass through the center of the loop (or are parallel to the plane of the loop),the net torque about any axis in the plane of the loop is zero.Specifically,the magnetic field is perpendicular to the plane of the loop,so the area vector $A$ is parallel to the magnetic field $B$. The torque is given by $	au = m 	imes B = mB \sin 	heta$. Since $	heta = 0^{\circ}$,the torque $	au = 0$.

$A$ current-carrying rectangular loop is placed near a straight infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is

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