The force acting on a current-carrying wire j | vedclass

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Question

(C) The magnetic force on a current-carrying wire of arbitrary shape in a uniform magnetic field is given by the formula $\vec{F} = I(\vec{L} 	imes \

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is independent of the shape of the wire

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(C) The magnetic force on a current-carrying wire of arbitrary shape in a uniform magnetic field is given by the formula $\vec{F} = I(\vec{L} 	imes \vec{B})$,where $\vec{L}$ is the vector displacement from the starting point $A$ to the ending point $B$.Since the points $A$ and $B$ are fixed,the displacement vector $\vec{L}$ remains the same regardless of the path (shape) taken by the wire between these two points.Therefore,the magnetic force depends only on the current $I$,the magnetic field $\vec{B}$,and the straight-line displacement vector $\vec{L}$ between the fixed points. It is independent of the actual shape of the wire.

The force acting on a current-carrying wire joining two fixed points $A$ and $B$ in a uniform magnetic field is:

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