The forbidden energy gap in Ge is 0.72 eV. Gi | vedclass

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(C) The energy required to generate an electron-hole pair is equal to the forbidden energy gap $E_{g}$.For a photon to create an electron-hole pair,it

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$17222$

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(C) The energy required to generate an electron-hole pair is equal to the forbidden energy gap $E_{g}$.For a photon to create an electron-hole pair,its energy must be at least equal to $E_{g}$.The relationship between energy and wavelength is given by $E = \frac{hc}{\lambda}$.To find the maximum wavelength $\lambda_{max}$,we use the minimum energy $E_{g}$:$\lambda_{max} = \frac{hc}{E_{g}}$Substituting the given values:$\lambda_{max} = \frac{12400 eV-Å}{0.72 eV}$$\lambda_{max} = 17222.22 Å$Rounding to the nearest integer,we get $\lambda_{max} = 17222 Å$.

$LIST$ $I$	$LIST$ $II$
$A$. Intrinsic Semiconductor	$I$. Fermi-level near conduction band
$B$. $n$-type semiconductor	$II$. Fermi-level at middle
$C$. $p$-type semiconductor	$III$. Fermi-level near valence band
$D$. Metals	$IV$. Fermi-level inside conduction band

The forbidden energy gap in $Ge$ is $0.72 eV$. Given $hc = 12400 eV-Å$. The maximum wavelength of radiation that will generate an electron-hole pair is: (in $Å$)

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