The following table gives the distribution of students of two sections according to the marks obtained by them:

Marks (Section $A$)	Frequency (Section $A$)	Marks (Section $B$)	Frequency (Section $B$)
$0-10$	$3$	$0-10$	$5$
$10-20$	$9$	$10-20$	$19$
$20-30$	$17$	$20-30$	$15$
$30-40$	$12$	$30-40$	$10$
$40-50$	$9$	$40-50$	$1$

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons,compare the performance of the two sections.

(N/A) We can find the class marks of the given class intervals by using the following formula:
$\text{Class mark} = \frac{\text{Upper class limit} + \text{Lower class limit}}{2}$

Marks	Class mark	Frequency (Section $A$)	Frequency (Section $B$)
$0-10$	$5$	$3$	$5$
$10-20$	$15$	$9$	$19$
$20-30$	$25$	$17$	$15$
$30-40$	$35$	$12$	$10$
$40-50$	$45$	$9$	$1$

By plotting the class marks on the $x$-axis and frequency on the $y$-axis,we draw the frequency polygons for both sections.
From the graph,it can be observed that the frequency polygon for section $A$ is shifted more towards the right compared to section $B$. This indicates that the students of section $A$ have performed better than the students of section $B$ in terms of obtaining higher marks.