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(B) First,arrange the data in ascending order of magnitude and calculate the cumulative frequency $(cf)$:						Height (in $cm$)			$150$			$152$			$154

Vedclass · Accepted Answer

$155$

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(B) First,arrange the data in ascending order of magnitude and calculate the cumulative frequency $(cf)$:						Height (in $cm$)			$150$			$152$			$154$			$155$			$156$			$160$			$161$							No of students $(f)$			$8$			$4$			$3$			$7$			$3$			$12$			$4$							Cumulative Frequency $(cf)$			$8$			$12$			$15$			$22$			$25$			$37$			$41$			Here,the total number of observations $N = 41$,which is an odd number.The median is the value of the $\left(\frac{N+1}{2}ight)^{	ext{th}}$ observation.Median $= \left(\frac{41+1}{2}ight)^{	ext{th}} = 21^{	ext{st}}$ observation.From the cumulative frequency table,we observe that the $21^{	ext{st}}$ observation falls in the range where the height is $155$ (since $cf$ for $154$ is $15$ and $cf$ for $155$ is $22$).Thus,the median is $155$.

Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
$f_i$	$8$	$30$	$40$	$12$	$10$

The following data gives the distribution of height of students:

Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$

No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$

The median of the distribution is:

Similar Questions

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The mean marks of $100$ students in a class in mathematics is $72$. If the number of boys is $70$ and their mean marks is $75$,find the mean marks of the girls in the class.

If for some $x \in R$,the frequency distribution of the marks obtained by $20$ students in a test is:
Marks: $2, 3, 5, 7$
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Then the mean of the marks is:

Find the median of the following frequency distribution.

Class $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$

$f_i$ $8$ $30$ $40$ $12$ $10$

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Height (in $cm$)	$160$	$150$	$152$	$161$	$156$	$154$	$155$
No of students	$12$	$8$	$4$	$4$	$3$	$3$	$7$

The following data gives the distribution of height of students: Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$ No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$ The median of the distribution is: