The mean and the median of the following ten | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the set of $10$ numbers: $10, 22, 26, 29, 34, x, 42, 67, 70, y$ in increasing order.$1$. Mean calculation:$	ext{Mean} = \frac{10 + 22 + 26

Vedclass · Accepted Answer

$\frac{7}{3}$

Vedclass · Answer

(A) Given the set of $10$ numbers: $10, 22, 26, 29, 34, x, 42, 67, 70, y$ in increasing order.$1$. Mean calculation:$	ext{Mean} = \frac{10 + 22 + 26 + 29 + 34 + x + 42 + 67 + 70 + y}{10} = 42$$300 + x + y = 420$$x + y = 120 \quad \dots (i)$$2$. Median calculation:For $10$ observations,the median is the average of the $5^{th}$ and $6^{th}$ terms.$	ext{Median} = \frac{34 + x}{2} = 35$$34 + x = 70$$x = 36$$3$. Finding $y$:Substitute $x = 36$ into equation $(i)$:$36 + y = 120$$y = 84$$4$. Final ratio:$\frac{y}{x} = \frac{84}{36} = \frac{7}{3}$

Height (in $cm$)	$160$	$150$	$152$	$161$	$156$	$154$	$155$
No of students	$12$	$8$	$4$	$4$	$3$	$3$	$7$

The mean and the median of the following ten numbers in increasing order $10, 22, 26, 29, 34, x, 42, 67, 70, y$ are $42$ and $35$ respectively. Then,$\frac{y}{x}$ is equal to:

Similar Questions

If the mean of $3, 4, x, 7, 10$ is $6$,then the value of $x$ is

Find the mean of the following frequency distribution:

$x_i$ $3$ $6$ $9$ $12$

$f_i$ $1$ $2$ $3$ $4$

The observations $29, 32, 48, 50, x, x + 2, 72, 78, 84, 95$ are arranged in ascending order. If their median is $63$,what is the value of $x$?

Which formula is used to calculate the weighted mean?

The following data gives the distribution of height of students. The median of the distribution is:

Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$

No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$

Vedclass Test Series

Exam Paper Generator

Online Exam Module