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(B) To find the median,we first calculate the cumulative frequency $(c.f.)$:						Class			$f_i$			$c.f.$							$0 - 10$			$8$			$8$							$10 - 20$

Vedclass · Accepted Answer

$23$

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(B) To find the median,we first calculate the cumulative frequency $(c.f.)$:						Class			$f_i$			$c.f.$							$0 - 10$			$8$			$8$							$10 - 20$			$30$			$38$							$20 - 30$			$40$			$78$							$30 - 40$			$12$			$90$							$40 - 50$			$10$			$100$			Here,$N = 100$,so $\frac{N}{2} = \frac{100}{2} = 50$.The cumulative frequency just greater than $50$ is $78$,which corresponds to the class interval $20 - 30$.Thus,the median class is $20 - 30$.Here,$l = 20$,$f = 40$,$F = 38$,and $h = 10$.Median $= l + \left( \frac{\frac{N}{2} - F}{f} ight) 	imes h$$= 20 + \left( \frac{50 - 38}{40} ight) 	imes 10$$= 20 + \left( \frac{12}{40} ight) 	imes 10$$= 20 + 3 = 23$.

$x_i$	$5$	$8$	$11$	$14$	$17$
$f_i$	$4$	$5$	$6$	$10$	$20$

$x_i$	$3$	$6$	$10$	$12$	$7$	$15$
$f_i$	$3$	$4$	$2$	$8$	$13$	$10$

Find the median of the following frequency distribution.

Class $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$

$f_i$ $8$ $30$ $40$ $12$ $10$

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Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
$f_i$	$8$	$30$	$40$	$12$	$10$

Find the median of the following frequency distribution. Class $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $f_i$ $8$ $30$ $40$ $12$ $10$