The first stable compound of the dark reactio | vedclass

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Question

(A) In the Calvin cycle (dark reaction),the primary carboxylation step involves the fixation of $CO_2$ into a $5$-carbon compound called Ribulose $1,5

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Phosphoglyceric acid

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(A) In the Calvin cycle (dark reaction),the primary carboxylation step involves the fixation of $CO_2$ into a $5$-carbon compound called Ribulose $1,5$-bisphosphate $(RuBP)$.This reaction is catalyzed by the enzyme $RuBisCO$.The resulting product is an unstable $6$-carbon intermediate,which immediately breaks down into two molecules of $3$-phosphoglyceric acid ($3$-$PGA$).Since $3$-$PGA$ is the first stable compound formed in this process,it is considered the first stable product of the dark reaction.

The first stable compound of the dark reaction of photosynthesis is

Similar Questions

In photosynthesis,where do the reactions that do not require light occur?

In the Calvin cycle of $C_3$ plants,which molecule acts as the primary $CO_2$ acceptor?

In Calvin cycle,if one molecule of $RuBP$ is carboxylated then how many $PGA$ molecules will be formed?

What is required for the fixation of one $CO_2$ molecule in the Calvin cycle?

In the condensed schematic representation of the dark reaction of photosynthesis given below,steps are indicated by alphabets. Select the option where the alphabets are correctly identified.

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