In the condensed schematic representation of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The correct option is $A$. In the Calvin cycle (dark reaction),the process consists of three main stages: $1$. Carboxylation $(A)$: $CO_2$ is fixe

Vedclass · Accepted Answer

$A = CO_2$ fixation,$B =$ Phosphorylation,$C =$ Reduction,$D =$ Regeneration

Vedclass · Answer

(A) The correct option is $A$. In the Calvin cycle (dark reaction),the process consists of three main stages: $1$. Carboxylation $(A)$: $CO_2$ is fixed by $RuBP$ to form an unstable compound which breaks down into $PGA$. $2$. Reduction ($B$ and $C$): This involves two steps: - Phosphorylation $(B)$: $PGA$ is converted to $1,3$-bisphosphoglycerate using $ATP$. - Reduction $(C)$: $1,3$-bisphosphoglycerate is reduced to $G3P$ (or $3-PGA$ aldehyde) using $NADPH$. $3$. Regeneration $(D)$: $RuBP$ is regenerated from $RuMP$ using $ATP$ to continue the cycle.

In the condensed schematic representation of the dark reaction of photosynthesis given below,steps are indicated by alphabets. Select the option where the alphabets are correctly identified.

Similar Questions

Where does the dark reaction of photosynthesis take place?

Besides water and light,which is more essential as a raw material for food formation?

Do reactions of photosynthesis called as 'Dark Reaction' need light? Explain.

For the fixation of $1$ molecule of $CO_2$ in the Calvin cycle,how many molecules of $NADPH$ and $ATP$ are required?

In the $C_3$ pathway,the first stable product is $P$,and in the $C_4$ pathway,the first stable product is $Q$. Choose the correct option for $P$ and $Q$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module