If the force between the electron in the first Bohr orbit and the nucleus (proton) in hydrogen atom is $F$, then the force between them when the electron is in the second orbit is
If the force between the electron in the first Bohr orbit and the nucleus (proton) in hydrogen atom is $F$, then the force between them when the electron is in the second orbit is
- A
$4F$
- B
$F/4$
- C
$F/9$
- D
$F/16$
Similar Questions
Which scientist gave plum pudding model of the atom ?
Which scientist gave plum pudding model of the atom ?
What is the atomic number of gold ?
What is the atomic number of gold ?
In an alpha particle scattering experiment distance of closest approach for the $\alpha$ particle is $4.5 \times 10^{-14} \mathrm{~m}$. If target nucleus has atomic number $80$ , then maximum velocity of $\alpha$-particle is . . . . .. $\times 10^5$ $\mathrm{m} / \mathrm{s}$ approximately.
$\left(\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{SI}\right.$ unit, mass of $\alpha$ particle $=$ $\left.6.72 \times 10^{-27} \mathrm{~kg}\right)$
In an alpha particle scattering experiment distance of closest approach for the $\alpha$ particle is $4.5 \times 10^{-14} \mathrm{~m}$. If target nucleus has atomic number $80$ , then maximum velocity of $\alpha$-particle is . . . . .. $\times 10^5$ $\mathrm{m} / \mathrm{s}$ approximately.
$\left(\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{SI}\right.$ unit, mass of $\alpha$ particle $=$ $\left.6.72 \times 10^{-27} \mathrm{~kg}\right)$
- [JEE MAIN 2024]
In Bohr model of hydrogen atom, the force on the electron depends on the principle quantum number as
In Bohr model of hydrogen atom, the force on the electron depends on the principle quantum number as
In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number as
In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number as