The first diffraction minimum due to the sing | vedclass

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(C) For the first diffraction minimum in a single slit experiment, the condition is given by $d \sin 	heta = n\lambda$, where $n = 1$ for the first m

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$10 	imes 10^{-5} \,	ext{cm}$

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(C) For the first diffraction minimum in a single slit experiment, the condition is given by $d \sin 	heta = n\lambda$, where $n = 1$ for the first minimum.Given:$\lambda = 5000 \,\mathring{A} = 5000 	imes 10^{-8} \,	ext{cm} = 5 	imes 10^{-5} \,	ext{cm}$$	heta = 30^o$Substituting the values into the formula:$d \sin 30^o = 5000 	imes 10^{-8} \,	ext{cm}$$d 	imes (1/2) = 5000 	imes 10^{-8} \,	ext{cm}$$d = 2 	imes 5000 	imes 10^{-8} \,	ext{cm}$$d = 10000 	imes 10^{-8} \,	ext{cm} = 10 	imes 10^{-5} \,	ext{cm}$

The first diffraction minimum due to the single slit diffraction is seen at $\theta = 30^o$ for a light of wavelength $5000 \,\mathring{A}$ falling perpendicularly on the slit. The width of the slit is

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