Light of wavelength 5000 , mathring{A} is inc | vedclass

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(B) For a single slit diffraction,the condition for the $n^{th}$ minima is given by $a \sin 	heta = n \lambda$,where $a$ is the slit width,$	heta$ i

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$10^{-4} \, cm$

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(B) For a single slit diffraction,the condition for the $n^{th}$ minima is given by $a \sin 	heta = n \lambda$,where $a$ is the slit width,$	heta$ is the angular position,and $\lambda$ is the wavelength.For the first minima,$n = 1$.Given: $\lambda = 5000 \, \mathring{A} = 5000 	imes 10^{-10} \, m = 5 	imes 10^{-7} \, m$ and $	heta = 30^\circ$.Substituting the values into the formula: $a \sin 30^\circ = 1 	imes (5 	imes 10^{-7} \, m)$.Since $\sin 30^\circ = 0.5$,we have $a 	imes 0.5 = 5 	imes 10^{-7} \, m$.$a = \frac{5 	imes 10^{-7}}{0.5} = 10 	imes 10^{-7} \, m = 10^{-6} \, m$.Converting to centimeters: $10^{-6} \, m = 10^{-6} 	imes 10^2 \, cm = 10^{-4} \, cm$.

Light of wavelength $5000 \, \mathring{A}$ is incident on a single slit such that the angular position of the first minima is $30^\circ$. The width of the slit is:

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