The figure shows four wire loops,with edge le | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The motional electromotive force (e.m.f.) induced in a conductor moving through a magnetic field is given by the formula $\varepsilon = B l v$,whe

Vedclass · Accepted Answer

$({e_c} = {e_d}) > ({e_a} = {e_b})$

Vedclass · Answer

(B) The motional electromotive force (e.m.f.) induced in a conductor moving through a magnetic field is given by the formula $\varepsilon = B l v$,where $B$ is the magnetic field strength,$l$ is the length of the conductor perpendicular to the velocity vector,and $v$ is the velocity.In this case,the loops move horizontally into the magnetic field. The vertical sides of the loops act as the moving conductors that cut the magnetic field lines.Let $l$ be the vertical length of the loop. The induced e.m.f. is proportional to this vertical length $l$.From the figure,loops $c$ and $d$ have a vertical side length of $2L$,while loops $a$ and $b$ have a vertical side length of $L$.Since the velocity $v$ and magnetic field $B$ are the same for all loops,the induced e.m.f. $\varepsilon$ is greater for loops with a larger vertical side length.Therefore,$\varepsilon_c = \varepsilon_d = B(2L)v$ and $\varepsilon_a = \varepsilon_b = B(L)v$.Comparing these,we get $(\varepsilon_c = \varepsilon_d) > (\varepsilon_a = \varepsilon_b)$.

Similar Questions

If current $I$ is flowing in a closed circuit with total resistance $R$,the rate of production of heat energy in the loop as we pull it with a constant speed $V$ is ($L=$ length of conductor,$B=$ magnetic field).

$A$ conducting ring of radius $R$ is placed in a uniform inward magnetic field $\vec B$ as shown. If the ring is moving with velocity $\vec v$ in its plane,the induced $emf$ across the arc $PQ$ will be:

The loop shown moves with a constant velocity $V$ in a uniform magnetic field of magnetic induction $B$ directed into the paper. The potential difference between $P$ and $Q$ is:

$A$ rectangular wire loop of sides $5 \text{ cm}$ and $3 \text{ cm}$ with a small cut is moving away from an infinitely long straight wire carrying a current of $30 \text{ A}$ with a velocity of $20 \text{ ms}^{-1}$ as shown in the figure. The emf induced across the cut is (in $\mu V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module