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(A) The magnetic flux $\Phi$ through the loop is given by $\Phi = B \cdot A = B \pi r^2$.According to Faraday's law,the induced emf $\varepsilon$ is g

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$10$

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(A) The magnetic flux $\Phi$ through the loop is given by $\Phi = B \cdot A = B \pi r^2$.According to Faraday's law,the induced emf $\varepsilon$ is given by $\varepsilon = -\frac{d\Phi}{dt}$.Taking the magnitude,$\varepsilon = \left| \frac{d}{dt} (B \pi r^2) ight| = B \pi (2r) \frac{dr}{dt}$.Given values: $B = 0.8 \, T$,$r = 10 \, cm = 0.1 \, m$,and $\frac{dr}{dt} = -2 \, cm/s = -0.02 \, m/s$.Substituting the values:$\varepsilon = 0.8 	imes \pi 	imes 2 	imes 0.1 	imes 0.02$.$\varepsilon = 0.8 	imes \pi 	imes 0.004 = 0.0032 \pi \, V$.Using $\pi \approx 3.14159$,$\varepsilon \approx 0.0032 	imes 3.14159 \approx 0.010053 \, V$.Converting to millivolts $(mV)$: $\varepsilon \approx 10.053 \, mV$.Rounding to the nearest integer,we get $10 \, mV$.

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