(C) Total expenditure $= 560 + 420 + 180 + 160 + 120 = 1440$.The angle of the sector for clothes is calculated as:$\text{Angle} = \left( \frac{\text{E

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(C) Total expenditure $= 560 + 420 + 180 + 160 + 120 = 1440$.The angle of the sector for clothes is calculated as:$\text{Angle} = \left( \frac{\text{Expenditure on clothes}}{\text{Total expenditure}} \right) \times 360^o$$\text{Angle} = \left( \frac{180}{1440} \right) \times 360^o$$\text{Angle} = \frac{1}{8} \times 360^o = 45^o$.

Class 11 Mathematics Statistics Word problem -Statistics

Difficult

The expenditure of a family for a certain month were as follows:
Food - Rs. $560$,Rent - Rs. $420$,Clothes - Rs. $180$,Education - Rs. $160$,Other items - Rs. $120$
$A$ pie graph representing this data would show the expenditure for clothes by a sector whose angle equals......$^o$

A
$180$
B
$90$
C
$45$
D
$64$

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Statistics

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Word problem -Statistics

Two distributions $A$ and $B$ have the same mean. If their coefficients of variation are $6$ and $2$ respectively and $\sigma_A$ and $\sigma_B$ are their standard deviations,then:

EasyTS EAMCET 2018

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If $65$ is the range of the ungrouped data $50, 70, 60, B, 20, 40$,then the absolute difference of the possible values of $B$ is

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The mean and $S.D.$ of the marks of $200$ candidates were found to be $40$ and $15$ respectively. Later,it was discovered that a score of $40$ was wrongly read as $50$. The correct mean and $S.D.$ respectively are...

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The mean and standard deviation of $20$ observations are found to be $10$ and $2$ respectively. On rechecking,it was found that an observation $8$ was incorrect. If the incorrect observation $8$ is replaced by $12$,calculate the correct mean and standard deviation.

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The mean and variance of $n$ observations are $8$ and $16$, respectively. If the sum of the first $(n - 1)$ observations is $48$ and the sum of squares of the first $(n - 1)$ observations is $496$, then the value of $n$ is:

DifficultJEE MAIN 2026

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The expenditure of a family for a certain month were as follows:Food - Rs. $560$,Rent - Rs. $420$,Clothes - Rs. $180$,Education - Rs. $160$,Other items - Rs. $120$$A$ pie graph representing this data would show the expenditure for clothes by a sector whose angle equals......$^o$

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Two distributions $A$ and $B$ have the same mean. If their coefficients of variation are $6$ and $2$ respectively and $\sigma_A$ and $\sigma_B$ are their standard deviations,then:

If $65$ is the range of the ungrouped data $50, 70, 60, B, 20, 40$,then the absolute difference of the possible values of $B$ is

The mean and $S.D.$ of the marks of $200$ candidates were found to be $40$ and $15$ respectively. Later,it was discovered that a score of $40$ was wrongly read as $50$. The correct mean and $S.D.$ respectively are...

The mean and standard deviation of $20$ observations are found to be $10$ and $2$ respectively. On rechecking,it was found that an observation $8$ was incorrect. If the incorrect observation $8$ is replaced by $12$,calculate the correct mean and standard deviation.

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The expenditure of a family for a certain month were as follows:
Food - Rs. $560$,Rent - Rs. $420$,Clothes - Rs. $180$,Education - Rs. $160$,Other items - Rs. $120$
$A$ pie graph representing this data would show the expenditure for clothes by a sector whose angle equals......$^o$