The equivalent weight of a metal is 4.0. The | vedclass

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(A) Given,equivalent weight of metal $= 4.0$ and vapour density of metal chloride $= 59.25$.Molecular weight of metal chloride $= 2 	imes 	ext{V.D.}

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) Given,equivalent weight of metal $= 4.0$ and vapour density of metal chloride $= 59.25$.Molecular weight of metal chloride $= 2 	imes 	ext{V.D.} = 2 	imes 59.25 = 118.5$.Let the valency of the metal be $n$. The formula of the metal chloride is $MCl_n$.Molecular weight $= 	ext{Atomic weight of metal} + n 	imes 35.5$.Since $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes n$,we have $118.5 = 4n + 35.5n = 39.5n$.$n = \frac{118.5}{39.5} = 3$.Atomic weight $= 4 	imes 3 = 12$.

The equivalent weight of a metal is $4.0$. The vapour density of its chloride is $59.25$. Its atomic weight is

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