In the reaction SO_2 + 2H_2S rightarrow 3S + | vedclass

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(C) $1$. Identify the oxidizing agent: In the reaction $SO_2 + 2H_2S \rightarrow 3S + 2H_2O$,the oxidation state of $S$ in $SO_2$ changes from $+4$ to

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$16$

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(C) $1$. Identify the oxidizing agent: In the reaction $SO_2 + 2H_2S ightarrow 3S + 2H_2O$,the oxidation state of $S$ in $SO_2$ changes from $+4$ to $0$ (reduction),so $SO_2$ is the oxidizing agent.$2$. Calculate the change in oxidation state: The change in oxidation state per molecule of $SO_2$ is $|4 - 0| = 4$.$3$. Calculate the equivalent mass: The equivalent mass of an oxidizing agent is given by $\frac{	ext{Molar mass}}{	ext{Change in oxidation state}}$.$4$. Molar mass of $SO_2 = 32 + (2 	imes 16) = 64 \ g/mol$.$5$. Equivalent mass $= \frac{64}{4} = 16$.

In the reaction $SO_2 + 2H_2S \rightarrow 3S + 2H_2O$,the equivalent mass of the oxidizing agent is .....

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