The equivalent weight of a divalent metal is | vedclass

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(B) The atomic weight of a metal is given by the formula: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency}$.Given,$	ext{Equival

Vedclass · Accepted Answer

$\frac{63.64}{6.02 	imes 10^{23}}$

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(B) The atomic weight of a metal is given by the formula: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency}$.Given,$	ext{Equivalent weight} = 31.82$ and $	ext{Valency} = 2$ (for a divalent metal).Therefore,$	ext{Atomic weight} = 31.82 	imes 2 = 63.64 \ 	ext{g/mol}$.The weight of a single atom is calculated by dividing the atomic weight by Avogadro's number $(N_A = 6.02 	imes 10^{23} \ 	ext{atoms/mol})$.$	ext{Weight of one atom} = \frac{63.64}{6.02 	imes 10^{23}} \ 	ext{g}$.

The equivalent weight of a divalent metal is $31.82$. The weight of a single atom is

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