NaOH + H_3PO_4 to NaH_2PO_4 + H_2O; What is t | vedclass

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(D) In the given reaction,$NaOH + H_3PO_4 	o NaH_2PO_4 + H_2O$,$H_3PO_4$ reacts with $NaOH$ to form $NaH_2PO_4$. This indicates that $H_3PO_4$ loses

Vedclass · Accepted Answer

$98$

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(D) In the given reaction,$NaOH + H_3PO_4 	o NaH_2PO_4 + H_2O$,$H_3PO_4$ reacts with $NaOH$ to form $NaH_2PO_4$. This indicates that $H_3PO_4$ loses only one $H^+$ ion. Therefore,the basicity (n-factor) of $H_3PO_4$ in this reaction is $1$. Equivalent weight = $\frac{	ext{Molecular weight}}{	ext{n-factor}}$. Molecular weight of $H_3PO_4 = (3 	imes 1) + 31 + (4 	imes 16) = 98 \ g/mol$. Equivalent weight = $\frac{98}{1} = 98$.

Element	Atomic mass
$A$	$12.01$
$B$	$35.5$

$NaOH + H_3PO_4 \to NaH_2PO_4 + H_2O$; What is the equivalent weight of phosphoric acid in this reaction?

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