The equivalent weight of $H_3PO_4$ in the reaction is $Ca(OH)_2 + H_3PO_4 \to CaHPO_4 + 2H_2O$
$(Ca = 40, P = 31, O = 16)$
$(Ca = 40, P = 31, O = 16)$
- A$49$
- B$98$
- C$32.66$
- D$147$
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