In a reaction the ferrous (F{e^{ + 2 }}) iron | vedclass

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Question

(c)The atomic weight;

${\rm{Equivalent weight }} = {\rm{ }}\frac{{{\rm{Atomic weight}}}}{{{\rm{ No}}{\rm{. of }}{{\rm{e}}^--}{\rm{lost or gained}}}

Vedclass · Accepted Answer

The atomic weight

Vedclass · Answer

(c)The atomic weight;

${m{Equivalent weight }} = {m{ }}\frac{{{m{Atomic weight}}}}{{{m{ No}}{m{. of }}{{m{e}}^--}{m{lost or gained}}}}$

$F{e^{2 + }}\, 	o \,F{e^{3 + }} + {e^ - }$

 Equivalent weight = Atomic weight

In a reaction the ferrous $(F{e^{ + 2 }})$ iron is oxidised to ferric $(F{e^{ + 3 }})$ ion. The equivalent weight of the ion in the above reaction is equal to

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