The equation of wave motion is Y = 5 sin (10 | vedclass

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(C) The standard equation of a traveling wave is given by $y = A \sin (\omega t - kx + \phi)$ or $y = A \sin (kx - \omega t + \phi)$.Comparing the giv

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$500$

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(C) The standard equation of a traveling wave is given by $y = A \sin (\omega t - kx + \phi)$ or $y = A \sin (kx - \omega t + \phi)$.Comparing the given equation $Y = 5 \sin (10 \pi t - 0.02 \pi x + \pi / 3)$ with the standard form,we identify the angular frequency $\omega$ and the wave number $k$:$\omega = 10 \pi \ rad/s$$k = 0.02 \pi \ rad/m$The velocity of the wave $v$ is given by the ratio of angular frequency to wave number:$v = \frac{\omega}{k}$Substituting the values:$v = \frac{10 \pi}{0.02 \pi}$$v = \frac{10}{0.02} = \frac{1000}{2} = 500 \ m/s$Therefore,the velocity of the wave is $500 \ m/s$.

The equation of wave motion is $Y = 5 \sin (10 \pi t - 0.02 \pi x + \pi / 3)$ where $x$ is in $m$ and $t$ is in $s$. The velocity of the wave is (in $m/s$)

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