The equation of the plane passing through the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The direction ratios of the line joining the points $(-3, 1, 2)$ and $(2, 3, 4)$ are $(2 - (-3)), (3 - 1), (4 - 2)$,which are $5, 2, 2$.Since the

Vedclass · Accepted Answer

$\bar{r} \cdot (5\hat{i} + 2\hat{j} + 2\hat{k}) = 1$

Vedclass · Answer

(A) The direction ratios of the line joining the points $(-3, 1, 2)$ and $(2, 3, 4)$ are $(2 - (-3)), (3 - 1), (4 - 2)$,which are $5, 2, 2$.Since the plane is perpendicular to this line,the normal vector to the plane is $\vec{n} = 5\hat{i} + 2\hat{j} + 2\hat{k}$.The equation of a plane passing through a point $\vec{a} = -\hat{i} + 2\hat{j} + \hat{k}$ with normal $\vec{n}$ is given by $(\vec{r} - \vec{a}) \cdot \vec{n} = 0$.Substituting the values,we get $(\vec{r} - (-\hat{i} + 2\hat{j} + \hat{k})) \cdot (5\hat{i} + 2\hat{j} + 2\hat{k}) = 0$.This simplifies to $\vec{r} \cdot (5\hat{i} + 2\hat{j} + 2\hat{k}) = (-\hat{i} + 2\hat{j} + \hat{k}) \cdot (5\hat{i} + 2\hat{j} + 2\hat{k})$.Calculating the dot product on the right side: $(-1)(5) + (2)(2) + (1)(2) = -5 + 4 + 2 = 1$.Thus,the equation of the plane is $\vec{r} \cdot (5\hat{i} + 2\hat{j} + 2\hat{k}) = 1$.

The equation of the plane passing through the point $(-1, 2, 1)$ and perpendicular to the line joining the points $(-3, 1, 2)$ and $(2, 3, 4)$ is $.........$

Similar Questions

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane $5y + 8 = 0$.

If from a point $P(a, b, c)$,perpendiculars $PA$ and $PB$ are drawn to $YZ$ and $ZX$ planes respectively,then the equation of the plane $OAB$ is

The coordinates of the foot of the perpendicular drawn from the origin to a plane is $(2, 4, -3)$. The equation of the plane is

If $P$ is the point $(2, 6, 3)$,then the equation of the plane passing through $P$ and perpendicular to $OP$,where $O$ is the origin,is:

If the plane $\frac{x}{2} + \frac{y}{3} + \frac{z}{3} = 1$ intersects the coordinate axes at $A, B, C$,then the area of $\Delta ABC$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module