The equation of the line joining the points ( | vedclass

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(B) Given points are $A(-3, 4, 11)$ and $B(1, -2, 7)$.Direction ratios of the line $AB$ are given by $(x_2 - x_1, y_2 - y_1, z_2 - z_1) = (1 - (-3), -

Vedclass · Accepted Answer

$\frac{x+3}{-2} = \frac{y-4}{3} = \frac{z-11}{2}$

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(B) Given points are $A(-3, 4, 11)$ and $B(1, -2, 7)$.Direction ratios of the line $AB$ are given by $(x_2 - x_1, y_2 - y_1, z_2 - z_1) = (1 - (-3), -2 - 4, 7 - 11) = (4, -6, -4)$.Dividing by $-2$,we get the simplified direction ratios as $(-2, 3, 2)$.The equation of a line passing through $(x_1, y_1, z_1)$ with direction ratios $(a, b, c)$ is $\frac{x - x_1}{a} = \frac{y - y_1}{b} = \frac{z - z_1}{c}$.Substituting the point $(-3, 4, 11)$ and direction ratios $(-2, 3, 2)$,we get $\frac{x - (-3)}{-2} = \frac{y - 4}{3} = \frac{z - 11}{2}$.Thus,the equation is $\frac{x + 3}{-2} = \frac{y - 4}{3} = \frac{z - 11}{2}$.

The equation of the line joining the points $(-3, 4, 11)$ and $(1, -2, 7)$ is

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