The equation of a transverse wave travelling along a string is $y(x, t) = 4.0 \sin(20 \times 10^{-3} x + 600 t) \ mm$,where $x$ is in $mm$ and $t$ is in seconds. The velocity of the wave is:

Two waves are represented by: $x_1 = A \sin \left(\omega t + \frac{\pi}{6}\right)$ and $x_2 = A \cos \omega t$. Then the phase difference between them is

$A$ wave equation which gives the displacement along $y$-direction is given by $y = 0.001 \sin(100t + x)$,where $x$ and $y$ are in meters and $t$ is time in seconds. This represents a wave:

The figure represents the instantaneous picture of a transverse harmonic wave travelling along the negative $x$-axis. Identify the correct statement(s) related to the movement of the points shown in the figure. The points moving opposite to the direction of propagation (i.e., moving in the negative $y$-direction) are:

$A$ transverse wave travelling along a stretched string has a speed of $30 \ m/s$ and a frequency of $250 \ Hz$. The phase difference between two points on the string $10 \ cm$ apart at the same instant is

The phase difference corresponding to a path difference of $x$ is