The equation $x^2 + k_1 y^2 + k_2 xy = 0$ represents a pair of perpendicular lines,if

  • A
    $k_1 = -1$
  • B
    $k_1 = 2k_2$
  • C
    $2k_1 = k_2$
  • D
    None of these

Explore More

Similar Questions

The acute angle between the lines represented by $({x^2} + {y^2})\sqrt{3} = 4xy$ is

The angle between the lines represented by the equation $x^{2}-xy-6y^{2}-7x+31y-18=0$ is

If the angle between the lines given by the equation $x^{2}-3xy+\lambda y^{2}+3x-5y+2=0$,$\lambda \geq 0$,is $\tan^{-1}\left(\frac{1}{3}\right)$,then $\lambda=$

If the angle between the pair of straight lines represented by the equation ${x^2} - 3xy + \lambda {y^2} + 3x - 5y + 2 = 0$ is ${\tan ^{ - 1}}\left( {\frac{1}{3}} \right)$,where $\lambda$ is a non-negative real number,then $\lambda$ is:

Four different pairs of lines are given in List-$I$ and the cosine of the angle between every pair of lines is given in List-$II$. Match the following:
List-$I$List-$II$
$(A)$ $5x^2 + 2\sqrt{7}xy - y^2 = 0$$(I)$ $\frac{\sqrt{3}}{2}$
$(B)$ $x^2 + \sqrt{11}xy + 2y^2 = 0$$(II)$ $\frac{1}{2\sqrt{3}}$
$(C)$ $x^2 + 2\sqrt{2}xy + y^2 = 0$$(III)$ $\frac{1}{2}$
$(D)$ $3x^2 + 4\sqrt{2}xy + y^2 = 0$$(IV)$ $\frac{2}{3}$
$(V)$ $\frac{1}{\sqrt{2}}$

The correct match is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo