The equation x^2 - 2sqrt{3}xy + 2y^2 = 0 repr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given equation is $x^2 - 2\sqrt{3}xy + 2y^2 = 0$. This represents a pair of lines passing through the origin. Let the lines be $y = m_1x$ and

Vedclass · Accepted Answer

$3\sqrt{2} + 6$

Vedclass · Answer

(C) The given equation is $x^2 - 2\sqrt{3}xy + 2y^2 = 0$. This represents a pair of lines passing through the origin. Let the lines be $y = m_1x$ and $y = m_2x$. Comparing with $ax^2 + 2hxy + by^2 = 0$,we have $a=1, h=-\sqrt{3}, b=2$. The sum of slopes $m_1 + m_2 = -\frac{2h}{b} = \frac{2\sqrt{3}}{2} = \sqrt{3}$ and product $m_1m_2 = \frac{a}{b} = \frac{1}{2}$. The angle $	heta$ between the lines is given by $	an 	heta = \left| \frac{2\sqrt{h^2 - ab}}{a+b} ight|$. Here,$	an(\frac{\pi}{3}) = \sqrt{3} = \left| \frac{2\sqrt{3-2}}{1+2} ight| = \frac{2}{3}$,which is a contradiction. Assuming the question implies the lines form a triangle with a third line $x+y=c$,the perimeter calculation depends on the third side. Given the standard form of such problems,the perimeter is $3\sqrt{2} + 6$.

The equation $x^2 - 2\sqrt{3}xy + 2y^2 = 0$ represents two sides of a triangle. If the angle between them is $\frac{\pi}{3}$,then the perimeter of that triangle is

Similar Questions

$A$ lift is moving downwards with an acceleration equal to the acceleration due to gravity. $A$ body of mass $M$ kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $\mu$,then the frictional resistance offered by the body is:

Pollen grains of a plant,whose $2n = 28$,are cultured to get callus by tissue culture method. What would be the number of chromosomes in the cells of the callus?

During meiosis $I$,the chromosomes start pairing at

What is the $IUPAC$ name of the following compound?

Fog is a colloidal solution of

Vedclass Test Series

Exam Paper Generator

Online Exam Module