The engine of a jet aircraft applies a thrust | vedclass

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(B) Given:Thrust force $F = 10^5 \ N$Final velocity $v = 1 \ km/s = 1000 \ m/s = 10^3 \ m/s$Initial velocity $u = 0 \ m/s$Time $t = 10 \ s$Step $1$: C

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$10^3 \ kg$

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(B) Given:Thrust force $F = 10^5 \ N$Final velocity $v = 1 \ km/s = 1000 \ m/s = 10^3 \ m/s$Initial velocity $u = 0 \ m/s$Time $t = 10 \ s$Step $1$: Calculate the acceleration $(a)$ of the jet.Using the formula $a = \frac{v - u}{t}$:$a = \frac{10^3 \ m/s - 0}{10 \ s} = \frac{1000}{10} = 100 \ m/s^2 = 10^2 \ m/s^2$Step $2$: Calculate the mass $(m)$ of the plane using Newton's Second Law $(F = ma)$.$m = \frac{F}{a}$$m = \frac{10^5 \ N}{10^2 \ m/s^2} = 10^3 \ kg$Therefore,the mass of the plane is $10^3 \ kg$.

The engine of a jet aircraft applies a thrust force of $10^5 \ N$ during take-off and causes the plane to attain a velocity of $1 \ km/s$ in $10 \ s$. The mass of the plane is:

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